树莓派从 DHT11 温度湿度传感器读取数据

DHT11_Pins
时序图参考厂家说明书:DHT11数字湿温度传感器的原理和应用范例
四个阵脚连接:VCC接3.3伏电源,Dout接GPIO口,我接的是物理12针脚,NC留空,GND接地。
波折1:电阻被错接进了VCC,于是看了无数遍时序图,改了无数遍的驱动无论怎么改都是读不出数据。
波折2:偶然看了网上的DHT11上拉电阻电路图才发现错误,于是果断去掉电阻。但为了显示传感器工作正常在电源和VCC间接了个发光二极管进去,数据倒是读出来了,但各种错误。(原因不明)
去掉了电阻,去掉了led,优化了写的python,读数正常。再一次赞一个python。
写DHT11的驱动需要注意时序之间很紧密,python执行任何程序都要花费时间,在获取时序时需要注意所写调试用的代码也是占用时序的,在这一点上也走了一点弯路。

-- coding: utf-8 --

"""
Created on Sun Jan 26 14:24:43 2014

@author: pi
"""

import RPi.GPIO as gpio
import time
gpio.setwarnings(False)
gpio.setmode(gpio.BOARD)
time.sleep(1)
data=[]
def delay(i): #20*i usdelay
a=0
for j in range(i):
a+1
j=0
#start work
gpio.setup(12,gpio.OUT)
#gpio.output(12,gpio.HIGH)
#delay(10)
gpio.output(12,gpio.LOW)
time.sleep(0.02)
gpio.output(12,gpio.HIGH)
i=1
i=1

#wait to response
gpio.setup(12,gpio.IN)

while gpio.input(12)==1:
continue

while gpio.input(12)==0:
continue

while gpio.input(12)==1:
continue
#get data

while j<40:
k=0
while gpio.input(12)==0:
continue

while gpio.input(12)==1:
    k+=1
    if k&gt;100:break
if k&lt;3:
    data.append(0)
else:
    data.append(1)
j+=1

print "Sensor is working"
#get temperature
humidity_bit=data[0:8]
humidity_point_bit=data[8:16]
temperature_bit=data[16:24]
temperature_point_bit=data[24:32]
check_bit=data[32:40]

humidity=0
humidity_point=0
temperature=0
temperature_point=0
check=0

for i in range(8):
humidity+=humidity_bit[i]2(7-i)
humidity_point+=humidity_point_bit[i]
2(7-i)
temperature+=temperature_bit[i]2(7-i)
temperature_point+=temperature_point_bit[i]
2
(7-i)
check+=check_bit[i]2*(7-i)

tmp=humidity+humidity_point+temperature+temperature_point
if check==tmp:
print "temperature is ", temperature,"wet is ",humidity,"%"
else:
print "something is worong the humidity,humidity_point,temperature,temperature_point,check is",humidity,humidity_point,temperature,temperature_point,check

测试python程序时间代码

-- coding: utf-8 --

"""
Created on Sun Jan 26 16:01:59 2014

@author: pi
"""

import time
def delay(i):
k=0
for j in range(i):
k+=1
n=5000
j=0

a=time.time()
i=1
c=time.time()
d=c-a
print d

a=time.time()
for i in range(n):
j+=1
c=time.time()
d=c-a
print d

a=time.time()
delay(n)
c=time.time()
d=c-a
print d

via

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